A tenant space has the following areas and lighting power densities: 720 sf. of

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试卷: LEED AP ID+C 模拟试卷D[查看]
A tenant space has the following areas and lighting power densities: 720 sf. of enclosed offices with a lighting power density of 1.1 watts/sf 15,180 sf. of open offices with a lighting power density of 1.3 watts/sf The project has an installed interior lighting power of 13,145 watts. Using the space-by-space method how many points can this project earn for reducing the lighting power?
A: 4
B: 5
C: 3
D: 2

参考答案: B

本题解释:
Notes:

Reference: Energy and Atmosphere Credit, Optimize Energy Performance-Lighting Power, Calculations

The total floor area is 720 sf + 15,180 sf = 15,900 sf

The lighting power allowance of the enclosed offices is 720 sf X 1.1 watts/sf = 792 watts

The lighting power allowance of the open offices is 15,180 sf X 1.3 watts/sf = 19,734 watts

The total interior lighting power allowance is 792 watts + 19,734 watts = 20,526 watts

The percent reduction is calculated as:

Percent reduction = Lighting power reduction (watts) / Interior lighting power allowance (watts)

The lighting power reduction = Interior lighting power allowance (watts) - Installed interior lighting power (watts)

Lighting power reduction = 20,526 watts - 13,145 watts = 7,381 watts

Percent reduction = 7,381 watts / 20,526 watts = 35.9%

A 35.9% reduction can earn 5 points.